Two liquids X and Y on mixing form an ideal solution. The vapour pressure of the solution containing 3 mol of X and 1 mole of Y is 550 mm of Hg. But when 4 mol of X and 1 mol of Y are mixed, the vapour pressure of the solution thus, formed is 560 mm of Hg. what will be the vapour pressure of the pure X and pure Y at this temperature?

The lquid A and B from ideal solutions. At 300 K, the vapour pressure of solution containing 1 mole of A and 3 mole of B is 550 mm Hg. At the same tempreature, if one more mole of B is added to this solution, the vapour pressure of the solution increases by 10 mm Hg. determinethe vapour pressure of A and B in their pure states (in mm Hg):

Why the vapour pressure of saline solutions is lower than that of pure water ?

For a binary ideal liquid solution, the total vapour of the solution is given as:

If the vapor pressure of a dilute aqueous solution of glucose is 750 mm of Hg at 373 K , then molality of solute is

The vapour pressure of a give liquid will decrease if :

An ideal solution was found to have a vapour pressure of 80 torr when the mole fraction of a non-volatile solute was 0.2. What would be the vapour pressure of the pure solvent at the same temperature?

The vapour pressure of a liquid in a closed container depends upon

Vapour pressure of water at 20^C is 17.5 mm of Hg and lowering of vapour pressure of a sugar soluton is 0.061 mm of Hg. Calculate vapour pressure of the solution.