At `20^@C` the vapour pressure of pure liquid A is 22 mm Hg and that of pure liquid B is 75mm Hg. What is the composition of the solutions of these two components that has a vapour pressure of 48.5 mm Hg at this temperature?

At 25^@C the vapour pressure of pure water is 23.76 mm of Hg and that of an aqueous dilute solution of urea is 22.98 mm of Hg. Calculate the molality of the solution.

The vapour pressure of pure liquids A and B are 450 and 700 mm Hg at 350 K respectively. Find out the composition of the liquid mixture if total vapour pressure is 600 mm Hg. Also find the composition of the vapour phase.

What is the effect of temperature on vapour pressure of a liquid ?

Vapour pressure of dilute aq. solution of glucose is 750 mm of Hg at 373 K. The mole fraction of the solute is ( p^@ water = 760 mm of Hg)

100 g of liquid A (molar mass 140 g mol^(-1) was dissolved in 1000 g of liquid B (molar mass 180 g mol^(-1)) . The vapour pressure of pure liquid B was found to be 500 torr. Calculate the vapour pressure of pure liquid A and its vapour pressure in the solution if the total vapour pressure of the solution is 475 Torr.

If the vapor pressure of a dilute aqueous solution of glucose is 750 mm of Hg at 373 K , then molality of solute is

At 100^@C , the vapour pressure of a solution of 6.5 g of solute in 100 g of water is 732 mm. If k_b is 0.52 klm, the boiling point of solution will be:

At 25^(@)C , the vapour pressure of pure liquid A (mol. Mas = 40) is 100 torr, and pure liquid B is 40 torr (mol. = 80). The vapour pressure at 25^(@)C of a solution containing 20 g of each A and B is :

What happens to the vapour pressure of a liquid when a non-volatile solute is added to it