When 2.56g of sulphur was dissolved in 100 g of `CS_2`, the freezing point lowered by 0.383K. Calculate the formula of sulphur `(S_x)`.
`(k_(f)` for `CS_2`= `3.83K kg mol^-1`, Atomic mass of sulphur =`32g mol^-1)`.

The boiling point of Benzene (C_(6) H_(6)) is 353.23 K. When 1 . 80 g of a non - volatile solute was dissolved in 90 g of C_(6) H_(6) the boiling point is raised to 354 . 11 K. Calculate the molar mass of solute . (Given K_(b) for benzene is 2 . 53 K kg mol^(-1) )

Boiling point of benzene is 353.23 K . When 1 . 80 g of non-volatile solute was dissolved in 90 g of benzene the boiling point is raised to 354. 11 K? Calculate molar mass of solute . ( K_(b) for benzene is 2 . 53 K kg mol^(-1) )

The freezing point of a solution containing 0.3 g of acetic acid in 30.0 g of benzene is lowered by 0.45^@ . Calculate the Van's Hoff factor. (K_f for benzene=5.12K kg mol^-1) .

10g of non-volatile solute when dissolved in 100g of benzene raises its boiling point by 1^@ C. What is the molecular mass of the solute. ( k_b for benzene=2.53 K kg mol^-1 )

On dissolving 3.24g of sulphur in 40g of benzene, boiling point of solution was higher than that of benzene by 0.81K. K_b value for benzene is 2.53K kg mol^-1 . What is the molecular formula of sulphur? (Atomic mass of sulphur=32 g mol^-1) .

Calculate the freezing point of a one molar aqueous solutoin (density 1.04gL^-1) of KCl. ( K_f of water=1.86Kg mol^-1 , atomic masses of K=39, Cl=35.5)

15 g of an unknown molecular substance was dissolved in 450 g of water. The resulting solution freezes at - 0 . 34^(@) C . What is them molar ass of the substance ? ( K_(f) for water = 1. 86 K kg mol^(-1) )

2.82g of glucose (Molar mass: 180g mol^-1 ) are dissolved in 30g of water . Calculate mole fraction of glucose and water.

45g of ethylene glycol (C_2H_6O_2) is mixed with 600 g of water. Calculate: the freezing point of the solution. (K_f for water=1.86K kg mol^-1) .