2g of benzoic acid (`C_6H_5COOH`) is dissolved in 25g of benzene show depression in freezing point equal to 1.62K. Molar depression constant for benzene, `K_f`=4.9K `kg mol^-1`. What is percentage association of acid if it forms a dimer in solution?

5 . 0 g of phenol dissolved in 250 g of benzene shows a depression in freezing point equal to 0 . 70^(@) C. What is the percentage association of phenol ? ( K_(f) for benzene = 5.12 K kg. MOL^(-1) )

A solution of 1.25 g of P in 50 g of water lowers freezing point by 0.3K . Molar mass of P is 94 and k_f(water)=1.86K kg mol^-1) . The degree of association of P if it forms dimers in water is

1.00g of a non-electrolyte solute dissolved in 50g of benzene lowered the freezing point of benzene by 0.40K. The freezing point depression constant of benzene is 5.12K mol^-1 . Find the molar mass of the solute.

3.9 g of benzoic acid dissolved in 49 g of benzene shows a depression in freezing point of 1.62K. Calculate the Van't Hoff factor and predict the nature of solute (associated or dissociated). (Given: Molar mass of benzoic acid= 122 gmol^-1 , K_f for benzene= 49 K kg mol^-1 )

2.1 g of non-electrolyte solute (molar mass 250 g/mol) was dissolved in 5.12 g of benzene. If the freezing point of depression constant, k_f of benzene is 5.12 K kg/mol, Calculate the freezing point of benzene.

1 g of non - electrolyte solute (molar mass 250 g/mol) was dissolved in 5.12g of benzene. If the freezing point of depression constant, k_f of benzene is 5.12 K kg/mol, the freezing point of benzene will be lowered by

Two elements A and B form compounds having formula AB2 and AB4. When dissolved in 20 g of benzene (C_6H_6), 1 g of AB_2 lowers the freezing point by 2.3 K whereas 1.0 g of AB_4 lowers it by 1.3 K. The molar depression constant for benzene is 5.1 K kg mol^(-1) . Calculate atomic masses of A and B.

1 . 5 of Ba (NO_(3))_(2) dissolved in 100 g of water shows a depression in freezing point equal to 0 . 28^(@)C . What is the percentage dissociation of the salt ? ( K_(f) for water = 1 . 86 K/m and molar mass of Ba (NO_(3))_(2) = 261.)

Calculate depression of freezing point for 0.56 molal aq. Solution of KCl. (Given : K_f(H_(2)O) = 1.8 kg mol^(-1) ).