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Why is it advised to add ethylene glycol...

Why is it advised to add ethylene glycol to water in a car radiator while driving in a hill station.

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Ethylene glycol is added to water as an antifreeze. It will

Why it is not advised to wear polyester clothes while working in a kitchen?

A 0.5 molal solution of ethylene glycol water is used as coolant in a car. If the freezing point constant of water be 1.86^(@)C per mole, the mixture shall freeze at

Properties such as boiling point, freezing point and vapour pressure of a pure solvent change when solute molecules are added to get a homogeneous solution. These are called colligative properties. Applications of colligative properties are very useful in day-to-day life One of its examples is the use of ethylene glycol and water mixture as an anti-freezing liquid in the radiator of automobiles.A solution M is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is 0.9.Given: Freezing point depression constant of water (Kfwater​)=1.86Kkgmol−1Freezing point depression constant of ethanol(Kfethanol​)=2.0Kkgmol−1 Boiling point elevation constant of water(Kbwater​)=0.52Kkgmol−1 Boiling point elevation constant of ethanol (Kbethanol​)=1.2Kkgmol−1 Standard freezing point of water =273K Standard freezing point of ethanol =155.7K Standard boiling point of water =373K Standard boiling point of ethanol =351.5K Vapour pressure of pure water =32.8mmHg Vapour pressure of pure ethanol =40mmHg Molecular weight of water =18gmol−1 Molecular weight of ethanol =46gmol−1 In answering the following questions, consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative. Water is added to the solution M such that the mole faraction of water in the solution becomes 0.9. the boiling point of this solution is

In cold concentries, a solution of water and ethylene glycol is used as coolant in an automobile engine radiator instead of water. Explain

STATEMENT - 1 : addition of ethylene glycol to water lowers the freezing point of water, therefore, used as antifreeze substance. STATEMENT - 2 : Ethylene glycol is soluble in water.

The temperature of a city was found to be -9.3^(@) C. A car used, whose rasiator was filled with 5 L of water . What minimum quantity of antifreezing agent ethylene glycol were added to water of raiator in order to use the car for teavelling? ( K_(f) of water 1.86 k mol^(-1))

MODERN PUBLICATION-SOLUTIONS -EXERCISE
  1. Why is it advised to add ethylene glycol to water in a car radiator wh...

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  2. Calculate the percentage composition of C2H5OH.

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  3. 18g of glucose (molar mass 180gmol^-1) is present in 500cm^3 of its aq...

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  4. A solutionm of glucose (C6H12O6) in water is labelled as 10% by weight...

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  5. What volume of 10%(w/v) solution of Na2CO3 will be required to neutral...

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  6. What volume of 95 mass% sulphuric acid (density =1.85g/cm^3) and what ...

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  7. Calculate the mole fraction of ethanol and water in a sample of rectif...

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  8. Calculate the mole fraction of water in a mixture of 12 g water, 108 g...

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  9. One litre solution of N/2 HCl is heated in a beaker. It was observed t...

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  10. Concentrated H(2)SO(4) has a density 1 . 9 g/mL and is 99% H(2) SO(4)...

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  11. Calculate the molality and mole fraction of the solute in aqueous solu...

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  12. The molarity of a solution of ethyl alcohol (C2H5OH) in water in 1.55 ...

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  13. Commercially available concentrated HCI contains 38% HCI by mass an...

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  14. Calculate the formality of sodim thiosulphate (Na2S2O3.5H2O) solution,...

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  15. 4.0 g of NaOH are contained in one declitre of a solution. Calculate m...

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  16. 4.0 g of NaOH are contained in one declitre of a solution. Calculate m...

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  17. 4.0 g of NaOH are contained in one declitre of a solution. Calculate m...

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  18. Calculate molarity and molality of solution prepared by mixing equa...

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  19. The concentration of solution of sulphuric acid is 18M and has density...

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  20. Calculate the number of molecules of oxalic acid (H2C2O4. 2H2O) in 100...

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  21. The mole fraction of benzene in a solution with toluene 0.50 calculate...

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