45g of ethylene glycol `(C_2H_6O_2)` is mixed with 600 g of water. Calculate:
the freezing point of the solution.
`(K_f for water=1.86K kg mol^-1)`.

45g of ethylene glycol ( C_2H_6O_2 ) is mixed with 600g of water. Calculate The freezing point depression

31 gm of ethylene glycol (C_2H_6O_2) is mixed with 500 gm of solvent. (K_f = 2 K kg "mol"^(-1)) . What is the freezing point of the solution in K ? (freezing point of solvent = 273K)

An antifreeze solution is prepared fro, 222.6g of ethylene glycol, C_2H_4(OH)_2 and 200g of water. Calculate the molality of the solution . If the density of the solution is 1.072g mL^-1 , then what shall be the molarity of the solution?

K_f for water is 1.86K kg mol^-1 . If your automobile radiator holds 1.0 kg of water, how many grams of ethylene glycol (C_2H_6O_2) must you add to get the freezing point of the solution lowered to 0.8^@C ?

18 g of glucose is dissolved in 1 kg of water. At what temperature will the solution boil ? ( K_b for water is 0.52 K kg "mol"^(-1) )

How many grams of ethylene glycol (molar mass = 62) should be added to 10 kg of water, so that the resulting solution freezes at -10^(@)C ( K_(f) for water = 1.86 K "mol^(-1) ).

in a cold climate water gets frozen causing damage to the radiator of a car . Ethylene glycol is used as an antifreezing agent . Calculate the amount of ethylene glycol to be added to 4kg of water to prevent it from freezing at -6^@ C . ( K_f for water 1.85 Km^-1 ).