Why the vapour pressure of a solution of glucose in water is lower than of pure water

Why the vapour pressure of saline solutions is lower than that of pure water ?

The vapour pressure of an aqueous solution of glucose is 750 mm of mercury at 100^@ C . Mole fraction of solute will be

At 100^@C , the vapour pressure of a solution of 6.5 g of solute in 100 g of water is 732 mm. If k_b is 0.52 klm, the boiling point of solution will be:

The vapour pressure of water at 293K is 0.0231 bar and the vapour pressure of a solution of 108.24 g of a compound in 1000 g of water at the same temperature is 0.0228 bar. Calculate the molar mass of the solute.

Sea water is _______ dense than pure water.

Benzene and toluene form nearly ideal solution. At a certain temperature the vapour pressure of pure benzene and toluene are 150 and 50 torr. respectively. Calculate the vapour pressure of solution containing equal weights of benzene and toluene at this temperature .

How can you justify the observtation that the vapour pressure of the solution of a non-voltile solute in a given solvent is lower than that of the pure solvent. Also the laws concerning this observations.

Equal mass of a soute are dissolved in equal mass of two solvents A and B and formed very dilute solution. The relative lowering of vapour pressure for the solution B has twice the relative lowering of vapour pressure for the solution A. If m_(A) "and" M_(B) are the molecules mass of solventds A and B respectively, then :