The freezing point of a solution containing 0.2 g of acetic acid in benzene is lowered by `0.45^(@)C`. Colculate the degree of dimerization of acetic acid in benzene . `K_(f)` for benzene is 5.12 K`"mol"^(-1) `kg:

The freezing point of solution containing 0.2 g of acetic acid in 20.0 g of benzene is lowered by 0.45^(@)C . Calculate the degree of association of acetic acid in benzene. (K_(f)=5.12 K^(@) mol^(-1) kg^(-1))

Phenol associates in benzene to form a dimer (C_6H_5OH)_2 . The freezing point of a soluton contianing 5 g of phenol in 250 g of benzene is lowerd by 0.70^@C . Calculate the degree of association of phenol in benzene. (K_f for benzene=5.12 Km^-1)

The freezing point of a solution containing 0.3 g of acetic acid in 30.0 g of benzene is lowered by 0.45^@ . Calculate the Van's Hoff factor. (K_f for benzene=5.12K kg mol^-1) .

The boiling point of a solution containing 1.5 g of a dichlorobenzene in 100 g of benzene was higher by 0.268^@C . Calculate the molar mass of dichlorobenzene (K_b for benzene=2.62 degree molal^(-1)) .

One molal solution of a carboxylic acid in benzene shows the elevation of boiling point of 1.518 K. The degree of association for simerization of the acid in benzene is ( K_(b) for beznene = 2.53 K kg mol^(-1) ):

The freezing point of a solution containing 0.1g of K_3[Fe(CN)_6] in 100 g of water. (K_f=1.86 K kg mol^-1) is

phenol associates in benzene to a certain extent in dimerisation reaction. A solution containing 0.02 kg of phenol in 1.0 kg of benzene has its freezing point depressed 0.69 k. Hence, the degree of association of phenol demerized will be, [ K_(f)(C_(6)H_(6)) =5.12 k "mol"^(-1) ] a) 0.63 b) 0.73 c) 0.83 d) 0.93

Calculate molality of 2.5 g of ethanoic acid (CH_3COOH) in 75g benzene.

On dissolving 0.25 g of a non-volatile substance in 30 mL of benzene (density 0.8 g "mol"^(-1) ) its freezing point decreases by 0.40^(@)C . Calculate the molecular mass of the non-volatile substance. ( K_(f) for benzene is 5.12 k m^(-1) )

1.0 g of a monobassic acid HA in 100 g water lowers the freezing point by 0.155 K. IF 0.75 g, of same acid requires 25 mL of N/5 NaOH solution for complete neutralisation then %, degree of ionization of acid is ( K_(f) of H_(2)O = 1.86 K kg "mol"^(-1) ):