If 30 g a solute of molecular mass 154 is dissolved in 250 g of benzene. What will be the elevation in boiling point of the resuling solution ?
(Given : `K_B(C_(6)H_(6)) =2.6 K kg mol^(-1)`)

Calculate elevation in boiling point for 2 molal aqueous solution of glucose. (Given K_b(H_(2)O) = 0.5 kg mol^(-1) )

1.5 g of a non-volatile non-electrolyte is dissolved in 50 g of benzene (K_b=2.5K kg mol^-1) . The elevation of boiling point of the solution is 0.75K. The molecular weigth of the solute is gmol^-1 is

Boiling point of benzene is 353.23 K . When 1 . 80 g of non-volatile solute was dissolved in 90 g of benzene the boiling point is raised to 354. 11 K? Calculate molar mass of solute . ( K_(b) for benzene is 2 . 53 K kg mol^(-1) )

A solution containing 2.44 g of solute dissolved in 75 g of water boiled at 100.413^@C . What will be the molar mass of the solute?

5 . 0 g of phenol dissolved in 250 g of benzene shows a depression in freezing point equal to 0 . 70^(@) C. What is the percentage association of phenol ? ( K_(f) for benzene = 5.12 K kg. MOL^(-1) )

The boiling point of Benzene (C_(6) H_(6)) is 353.23 K. When 1 . 80 g of a non - volatile solute was dissolved in 90 g of C_(6) H_(6) the boiling point is raised to 354 . 11 K. Calculate the molar mass of solute . (Given K_(b) for benzene is 2 . 53 K kg mol^(-1) )

10g of non-volatile solute when dissolved in 100g of benzene raises its boiling point by 1^@ C. What is the molecular mass of the solute. ( k_b for benzene=2.53 K kg mol^-1 )

18 g of glucose is dissolved in 1 kg of water. At what temperature will the solution boil ? ( K_b for water is 0.52 K kg "mol"^(-1) )