A conductivity cell when filled with 0.01M KCl has a resistance of `74.5 ohm` at `25^@C`. When the same cell was filled with an aqueous solution of `0.05 M CaCl_2` solution the resistance was `876ohm`. Calculate
Molar conductivity of solution.

When a certain conductance cell was filled 0.1 mol L^-1 KCl, it has a resitance of 85 ohm and 25^@C . When the same cell was filled with an aqueous solution of 0.052 mol L^-1 of an electrolyte solution, the resistance was 96ohm . Calculate the molar conductivity of the electrolyte at this concentration. (conductivity of 0.1 mol L^-1 KCl solution is 1.29xx10^-2 S cm^-1 )

The resistance of a conductivity cell with 0.1 M KCl solution is found to be 200 ohm at 298K. When the same cell was filled with 0.02 M NaCl solution, the resistance at the same temperature is found to be 1100 ohm . Calculate: the molar conductivity of 0.02 M NaCl solution in S m^2 mol^-1 . Given: Conductivity of 0.1 M KCl solution at 298K = 1.29 S m^-1 .

The conductivity of 0.35M NaCl solution at 298K is 0.025 S/cm. Calculate its molar conductivity .

The resistance of a conductivity cell with 0.1 M KCl solution is found to be 200 ohm at 298K. When the same cell was filled with 0.02 M NaCl solution, the resistance at the same temperature is found to be 1100 ohm . Calculate: the cell constant of the cell in m^-1 . Given conductivity of 0.lM KCl is 1.29 Sm^(-1) ]

Resistance of a conductivity cell filled with 0.1 mol L^-1 KC1 solution is 100Omega .If the resistance of the same cell when filled with 0.02 mol L^(-1) KC1 solution is 520Omega , calculate the conductivity and molar conductivity of 0.02 mol L^(-1) KC1 solution. The conductivity of 0.1 mol L(-1) KCI solution is 1.29 S/m.

A conductivity cell has its electrodes 1 cm apart and each electrode has area of cross-section 2 cm^(2) , when filled with M/50 solution of sodium acetate, the cell shows a resistance of 166.5 ohms. Calculate the molar conductance of sodium acetate solution at the givne concentration.

A 0.05 M NaOH solution offered a resistance of 31.6 ohm ina conductivity cell at 298 K. if the area of the plates of the conductivity cell is 3.8 cm^2 and distance between them 1.4 cm. calculate the molar conductivity of the NaOH solution.

A cell when dippen in 0.5 M sucrose solution has no effect bbut when the same cell will be dippen in 0.5 M NaCI solution the celll will :

The molar conductivity of 1.5 M solution of an electrolysis is found to be 138.9 S cm^2 mol^-1 . Calculate the conductivity of this solution?