Calculate the limiting molar conductivity of `CaSO_4` limiting molar conductivities of calcium and sulphate ions are 119.0 and `106.0 Scm^2 mol^-1` respectively.

Limiting molar conductivity of NH_4OH is equal to

Define the following: Limiting molar conductivity?

Calculate the equivalent conductivity of 1M H2SO4 solution whose conductivity is 26 (10 ) s /cm

In infinite dilution of aqueous solution of BaCl_2 molar conductivity of Ba^(2+) and Cl^(-) ions are = 127.32 Scm^2 mol^-1 and 76.34Scm^2 mol^-1 respectively. What is Lambda_m for BaCl_2 at same dilution?

The limiting molar condcutance of sodium chloride, potassium chloride and potassium bromide are 126.45, 149.86 and 151.92 ohm^-1 cm^2 mol^-1 respectively. Calculate the limiting molar ionic conductance of Na^+ given that limiting molar ionic conductance of Br^- ion is 76.34 ohm^-1 cm^2 mol^-1 .

The molar conductivities at infinite dilution for sodium acetate, _hydrochloric acid and sodium cholride are 92.5,426.9 and 120.4 S cm^2mol^(-1) respectively at 298 K. Calculate the molar conductivity of acetic acid at infinite dilution.

Equivalent conductivity of Fe_(2)(SO_(4))_(3) is relative to molar conductivity by the expression :

A saturated solution in AgX(K_(sp)=3xx10^(-12)) and AgY(K_(sp)=10^(-12)) has conductivity 0.4xx10^(-6)Omega^(-1)cm^(-1) . Given: Limiting molar conductivity of Ag^+=60Omega^(-1)cm^2mol^(-1) Limiting molar conductivity of X^(-)=90Omega^(-1)cm^2mol^(-1) The conductivity of Y^(-) is (in Omega^(-1)cm^(-1) ):

The resistance of a conductivity cell with 0.1 M KCl solution is found to be 200 ohm at 298K. When the same cell was filled with 0.02 M NaCl solution, the resistance at the same temperature is found to be 1100 ohm . Calculate: the molar conductivity of 0.02 M NaCl solution in S m^2 mol^-1 . Given: Conductivity of 0.1 M KCl solution at 298K = 1.29 S m^-1 .