Resistance of a conductivity cell filled `0.1 molL^-1KCl` solution is `100 ohm`. If the resistance of the same cell when filled with `0.02molL^-1 KCl` solution is `520 ohm`, calculate the conductivity and molar conductivity of `0.02 mol L^-1` KCl solution. The conductivity of `0.1 mol L^-1` KCl solution is `1.29xx10^-2 cm^-1`?

Resistance of a conductivity cell filled with 0.1 mol L^-1 KC1 solution is 100Omega .If the resistance of the same cell when filled with 0.02 mol L^(-1) KC1 solution is 520Omega , calculate the conductivity and molar conductivity of 0.02 mol L^(-1) KC1 solution. The conductivity of 0.1 mol L(-1) KCI solution is 1.29 S/m.

The resistance of a conductivity cell with 0.1 M KCl solution is found to be 200 ohm at 298K. When the same cell was filled with 0.02 M NaCl solution, the resistance at the same temperature is found to be 1100 ohm . Calculate: the molar conductivity of 0.02 M NaCl solution in S m^2 mol^-1 . Given: Conductivity of 0.1 M KCl solution at 298K = 1.29 S m^-1 .

When a certain conductance cell was filled 0.1 mol L^-1 KCl, it has a resitance of 85 ohm and 25^@C . When the same cell was filled with an aqueous solution of 0.052 mol L^-1 of an electrolyte solution, the resistance was 96ohm . Calculate the molar conductivity of the electrolyte at this concentration. (conductivity of 0.1 mol L^-1 KCl solution is 1.29xx10^-2 S cm^-1 )

The resistance of a conductivity cell with 0.1 M KCl solution is found to be 200 ohm at 298K. When the same cell was filled with 0.02 M NaCl solution, the resistance at the same temperature is found to be 1100 ohm . Calculate: the cell constant of the cell in m^-1 . Given conductivity of 0.lM KCl is 1.29 Sm^(-1) ]

Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1M is 100 Omega . The conductivity of this solution is 1.29Sm^-1 . Resitance of the same cell when filled with 0.2 M of the same solution is 520Omega . The molar conductivity of 0.2 M solution of the electrolyte will be

The conductivity of 0.20 MKCl solution at 298 K is 0.0248 S cm^-1 . Calculate its molar conductivity.

The conductivity of 0.35M NaCl solution at 298K is 0.025 S/cm. Calculate its molar conductivity .

Calculate the equivalent conductivity of 1M H2SO4 solution whose conductivity is 26 (10 ) s /cm

The resistance of a conductivity cell containing 0.001M KC1 solution at 298 K is 1500 . What is the cell constant if conductivity of 0.001M KC1 solution at 298 K is 0.146 x 10“3 S cm-1.

The molar conductivity of a 0.5 mol/dm3 solution of AgNO3 with electrolytic conductivity of 5.76 x 10-3 S cm-1 at 298 K is