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Resistance of a conductivity cell filled...

Resistance of a conductivity cell filled with 0.1 mol `L^-1` KC1 solution is `100Omega`.If the resistance of the same cell when filled with 0.02 mol `L^(-1)` KC1 solution is `520Omega` , calculate the conductivity and molar conductivity of 0.02 mol `L^(-1)` KC1 solution. The conductivity of 0.1 mol `L(-1)` KCI solution is 1.29 S/m.

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Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1M is 100 Omega . The conductivity of this solution is 1.29Sm^-1 . Resitance of the same cell when filled with 0.2 M of the same solution is 520Omega . The molar conductivity of 0.2 M solution of the electrolyte will be

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The resistance of a conductivity cell with 0.1 M KCl solution is found to be 200 ohm at 298K. When the same cell was filled with 0.02 M NaCl solution, the resistance at the same temperature is found to be 1100 ohm . Calculate: the cell constant of the cell in m^-1 . Given conductivity of 0.lM KCl is 1.29 Sm^(-1) ]

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The resistance of a conductivity cell containing 0.001M KCl solution at 298K is 1500 Omega . What is the cell constant ( in mm^(-1) ) if the conductivity of 0.001M KCl solution is 2xx10^(-3)Smm^(-1)

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