Conductivity of 0.00241M acetic acid is ...

Conductivity of 0.00241M acetic acid is `7.896xx10^-5 S cm^-1`. Calculate its molar conductivity and if `Lambda^@` for acetic acid is `390.5 S cm^2 mol^-1`. What is its dissociation constant?

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Conductivity of 0.00241 M acetic acid is 7.896 x 10^(-5) S cm^(-1). Calculate its molar conductivity. If A°_m for acetic acid is 390.5 S cm^2 mol^(-1) , what is its dissociation constant?

The conductivity of 0.001028 mol L^(-1) acetic acid is 4.95 xx 10^-5 S cm^-1 . Calculate its dissociation constant if A_m^@ for acetic acid is 390.5 S cm^2 mol^(-1).

The conductivity of 0.35M NaCl solution at 298K is 0.025 S/cm. Calculate its molar conductivity .

The conductivity of 0.20 MKCl solution at 298 K is 0.0248 S cm^-1 . Calculate its molar conductivity.

The conductivity of 0.001 mol L^-1 solution of CH_3COOH is 3.905xx10^-5 S cm^-1 . Calculate the molar conductivity and degree of dissociation Give that lambda^@(H^+)=349.65 S cm^2 mol^-1 and lambda^@(CH_2COO^-40.9 S cm^2 mol^-1 .

The density of 2.05 M acetic acid in water is 1.02 g/ml . Calculate the molality of solution.

The molar concentration of acetic acid at infinite dilution is 390.7 S cm^2 mol^-1 . Calculate the molar condcutance of 0.01M acetic acid solution, given that the dissociation constant of acetic acid is 1.8xx10^-5

The density of a 2.05 M acetic acid in water is 1.02gcm^-3 . Calculate the molality of the solution.

The molar conductivity of 0.025 mol L^-1 methanoic acid is 46.1 S cm^2 mol^-1 . Calculate its degree of dissociation and dissociation constant. Given (H^+) = 349.6 S cm^2 mol^-1 and (HCOO ) = 54.6 S cm^2 mol^(-1).

The values of limiting ionic conductance of H+ and HCOO- ions are respectively 347 and 53 S cm2 mol−1 at 298K. If the molar conductance of 0.025M methanoic acid at 298K is 40 S cm2 mol-1 the dissociation constant of methanoic acid at 298K is

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