If `k_1` and `k_2` are rate constants at temperatures `T_1` and `T_2` respectively, then according to Arrhenius equation,

What is Kraft temperature (T_k) ?

Define rate constant (k).

Two rods X and Y are of equal lengths. Each rod has its ends at temperature T_1 and T_2 . What is the condition that will ensure equal rate of flow of heat through the rods X and Y?

The unit of 1 s t order rate constant are

Arrhenius studies the effect of temperature on the rate of a reaction and postulted that rate constant varies with temperature exponentially as k=Ae^(E_(a)//RT) . Thuis method is generally used for finding the activation energy of a reaction. Keeping temperature constant, the effect of catalyst on the activation energy has also been studied. The pre-exponetial factor in the Arrhenius equation of a first order reaction has the unit : a) mol L^(-1)s^(-1) b) L mol^(1)s^(-1) c) s^(-1) d) dimensionless

k_(1) and k_(2) are the velocity constants of forward and backward reactions. The equilibrium constant K of the reaction is

A carnot engine works between constant temps. T_1 and T_2 of source and sink resp. For efficiency to be greatest

A dilute solution contains 'x' moles of solute A in 1 kg of solvent with molal elevation constant K_(b) . The solute dimerises in the solution according to the following equation. The degree of association is (a) : 2A hArrA_(2) The van't Hoff factor will be: