When ln K is plotted against 1/T, the sl...

When ln K is plotted against 1/T, the slope was found to be `-10.7 xx 10^3 K` activation energy for the reaction would be :

`-78.9 kJ mol^-1`

`2.26 kJ mol^-1`

`88.9 kJ mol^-1`

`10.7 kJ mol^-1`

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