During the electrolysis of NaCl solution, the gas liberated at the anode is

Options

A. `Cl^(-) (aq.) rarr 1/2 Cl_2(g)+ e^(-) , E_(Cell)^(Theta) =1.36V`
B. `2H_2O(l) rarr O_2 (g)+ 4H^(+)+4e^(-), E_(Cell)^(Theta) =1.23V`
C. `Na^(+)(aq.)+ e^(-) rarr Na(s) ,E_(Cell)^(Theta) = 2.71 V`
D. `H^(+)(aq.)+ e^(-) rarr 1/2 H_2(g), E_(Cell)^(Theta) = 0.00 V`