Home
Class 12
CHEMISTRY
In the Hofmann bromamide degradation rea...

In the Hofmann bromamide degradation reaction, the number of moles of NaOH and `Br_2` used per mole of amine produced are

A

one mole of NaOH and one mole of `Br_2`

B

four moles of NaOH and two moles of `Br_2`

C

two moles of NaOH and two moles of `Br_2`

D

four moles of NaOH and one mole of `Br_2`.

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • ORGANIC COMPOUNDS CONTAINING NITROGEN

    MODERN PUBLICATION|Exercise EXERCISE |518 Videos

  • MOCK TEST 01

    MODERN PUBLICATION|Exercise EXERCISE|70 Videos

  • p-BLOCK ELEMENTS

    MODERN PUBLICATION|Exercise EXERCISE|1677 Videos

Similar Questions

Explore conceptually related problems

What is Hofmann bromamide degradation reaction ?

Calculate number of moles of Na2SO4 produced from 1 mole of NaOH when reacted with H2SO4.

Calculate the number of moles in the following : (2) 7.9 mg of Ca

Consider a titration of potassium dichromate solution with acidified Mohr’s salt solution using diphenylamine as indicator. The number of moles of Mohr’s salt required per mole of dichromate is

Calculate the number of molecules present in 0.5 moles of CO2 ?

Stannous sulphate (SnSO_(4)) and potassium permanganate are used as oxidising agents in acidic medium for oxidation of ferrrous ammnium sulphate to ferric sulphate. The ration of number of moles of stannous sulphate required per mole of ferrous ammonium sulphate to the number of moles of KMnO_(4) required per mole of ferrous ammonium sulphate, is:

"Equivalent mass" =("Molecular mass/Atomic mass" )/("n-factor") n-factor is very important in redox as well as non-redox reactions.With the help of n-factor we can predict the molar ratio of the reactant species specis taking part in reactions. The reciprocal of n-factor's ratio of the reactions is the molar ratio of the reactants. In general n-factor of acid/base is number of moles of H^(+)//OH^(-) furnished per mole of acid/base n-factor of a reactant is number of moles electrons lost or gained per mole of reactant. Example 1: (1)In acidic medium : KMnO_(4) (n=5)to Mn^(2+) (2) In neutral medium : KMnO_(4)(n=3) to Mn^(2+) (3) In basic medium : KMnO_(4)(n=1) to Mn^(6+) Example 2 : FeC_(2)O_(4)to Fe^(3+)+2CO_(2) Total number of moles e^(-) lost by 1 mole of FeC_(2)O_(4) =1+1xx2 implies 3 Consider the following reaction. H_(3)PO_(2)+NaOH to NaH_(2)PO_(2)+H_(2)O What is the equivalent mass of H_(3)PO_(2) ?(mol.Wt.is M)

"Equivalent mass" =("Molecular mass/Atomic mass" )/("n-factor") n-factor is very important in redox as well as non-redox reactions.With the help of n-factor we can predict the molar ratio of the reactant species specis taking part in reactions. The reciprocal of n-factor's ratio of the reactions is the molar ratio of the reactants. In general n-factor of acid/base is number of moles of H^(+)//OH^(-) furnished per mole of acid/base n-factor of a reactant is number of moles electrons lost or gained per mole of reactant. Example 1: (1)In acidic medium : KMnO_(4) (n=5)to Mn^(2+) (2) In neutral medium : KMnO_(4)(n=3) to Mn^(2+) (3) In basic medium : KMnO_(4)(n=1) to Mn^(6+) Example 2 : FeC_(2)O_(4)to Fe^(3+)+2CO_(2) Total number of moles e^(-) lost by 1 mole of FeC_(2)O_(4) =1+1xx2 implies 3 In the reaction, xVO+yFe_(2)O_(3) to FeO+V_(2)O_(5) what is the value of x and y respectively?

MODERN PUBLICATION-ORGANIC COMPOUNDS CONTAINING NITROGEN -EXERCISE
  1. Considering the basic strength of amines in aqueous solution, which on...

    Text Solution

    |

  2. On heating an aliphatic primary amine with chloroform and ethanolic po...

    Text Solution

    |

  3. In the Hofmann bromamide degradation reaction, the number of moles of ...

    Text Solution

    |

  4. The reaction of CHCl3 and alcoholic KOH with p-toluidine gives

    Text Solution

    |

  5. The correct order of increasing basic nature of the following bases is

    Text Solution

    |

  6. The final product in the following sequence of reaction is

    Text Solution

    |

  7. Choose the amide which on reduction with LiAlH4 yields a secondary ami...

    Text Solution

    |

  8. Mendius reaction converts an alkyl cyanide to

    Text Solution

    |

  9. The basicity of aniline is weaker in comparison to that of methyl amin...

    Text Solution

    |

  10. Aniline react with excess bromine in aqueous solution to give major pr...

    Text Solution

    |

  11. Which one of the following is the correct order of increasing basic st...

    Text Solution

    |

  12. Benzylamine is a stronger base than aniline because :

    Text Solution

    |

  13. The order of basic strength for methyl substituted amines in aqueous s...

    Text Solution

    |

  14. When aniline is nitrated with nitrating mixture in ice cold conditions...

    Text Solution

    |

  15. Which one of the following gives amine on heating with amide?

    Text Solution

    |

  16. A positive carbylamine test is given by

    Text Solution

    |

  17. Give reason for the following statement- Magnets are made up of an all...

    Text Solution

    |

  18. The best reagent for converting 2-phenylpropanamide into 2- phenylprop...

    Text Solution

    |

  19. The reaction of aniline with chloroform under alkaline conditions lead...

    Text Solution

    |

  20. The reagent with which the following reaction is best accomplished is

    Text Solution

    |