दो समतलो `2x+3y+4z=4` और `4x+6y=12` के बिच की दुरी है

2 x + 3y = 4, 4x + 6y = 12 .

2x = 3y = 4z, x: y: z

Solve : 2x+3y=6 4x+6y=12

Distance between the planes 2x + 3y + 4z = 4 and 4x + 6y + 8z = 12 is :

Distance between two planes 2x + 3y + 4z = 4 and 4x + 6y + 8z = 16 is :

The area (in sq. unit) of the triangle formed by the graphs of the equations x = 4, y =3 and 3x+4y = 12 is समीकरण x = 4, y =3 और 3x+4y = 12 के ग्राफ द्वारा बने त्रिभुज का क्षेत्रफल (वर्ग इकाई में) कितना है?

If 2x = 3y = 4z, find x:y: z.

Distance between two planes : 2x + 3y + 4z = 5 and 4x + 6y + 8z = 12 is :

Distance between the two planes : 2x + 3y + 4z = 4 and 4x + 6y + 8z = 12 is