The ratio of escape velocity at earth `(v_(e))` to the escape velocity at a planet `(v_(y))` whose radius and density are twice

The ratio of escape velocity at earth (v_(e)) to the escape velocity at a planet (v_(p)) whose radius and mean density in twice as that of earth is

The ratio of escape velocity at earth (v_e) to the escape velocity at a planet (v_p) whose radius and mean density are twice as that of earth is

The ratio of escape velocity at earth ( v_e ) to the escape velocity at a planet ( v_p ) whose radius and mean density are twice as that of earth is :

The escape velocity for the earth is v_(e) . The escape velocity for a planet whose radius is four times and density is nine times that of the earth, is

The escape velocity of a body from the earth is V_(e) . The escape velocity of a planet whose mass and radius are twice those of the earth is

The escape velocity from a planet is v_(0) . The escape velocity from a planet having twice the radius but same density will be

The escape velocity from the earth is 11 km//s . The escape velocity from a planet having twice the radius and same density as that of the earth is (in km//s )