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A telegraph post is bent at a point...

A telegraph post is bent at a point above the ground due to storm .Its top just meets the ground at a distance of `8sqrt(3)` metres from its foot and makes an angle of `30^(@)` , then the height of the post is :

A

16 metres

B

23 metres

C

24 metres

D

10 metres

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The correct Answer is:
To solve the problem, we need to find the height of the telegraph post that is bent due to a storm. We will use trigonometric ratios to determine the height. ### Step-by-Step Solution: 1. **Understanding the Problem**: - The telegraph post is bent at a point above the ground. - The top of the post touches the ground at a distance of \(8\sqrt{3}\) meters from its foot. - The angle formed with the ground is \(30^\circ\). 2. **Visualizing the Situation**: - We can visualize this scenario as a right triangle where: - \(A\) is the point where the post is bent. - \(B\) is the foot of the post. - \(C\) is the point where the top of the post touches the ground. - The distance \(BC\) (the horizontal distance from the foot of the post to the point where the top touches the ground) is \(8\sqrt{3}\) meters. 3. **Identifying the Triangle**: - In triangle \(ABC\): - \(AB\) is the vertical height of the post above point \(A\). - \(AC\) is the length of the post from point \(A\) to point \(C\) (the hypotenuse). - The angle \(CAB\) is \(30^\circ\). 4. **Using the Tangent Function**: - We can use the tangent function to find \(AB\): \[ \tan(30^\circ) = \frac{AB}{BC} \] - We know that \(\tan(30^\circ) = \frac{1}{\sqrt{3}}\) and \(BC = 8\sqrt{3}\): \[ \frac{1}{\sqrt{3}} = \frac{AB}{8\sqrt{3}} \] - Cross-multiplying gives: \[ AB = 8 \] 5. **Using the Sine Function**: - Now, we can use the sine function to find \(AC\): \[ \sin(30^\circ) = \frac{AB}{AC} \] - We know that \(\sin(30^\circ) = \frac{1}{2}\): \[ \frac{1}{2} = \frac{8}{AC} \] - Cross-multiplying gives: \[ AC = 16 \] 6. **Calculating the Total Height of the Post**: - The total height of the post is the sum of \(AB\) and \(AC\): \[ \text{Height of the post} = AB + AC = 8 + 16 = 24 \text{ meters} \] ### Final Answer: The height of the post is **24 meters**.
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