The angle of elevation of the top of a t...

The angle of elevation of the top of a tower standing on a horizontal plane from two points on a line passing through the foot of the tower at a distance 9 ft and 16 ft. respectively are complementary angles. The height of the tower is

`(h(cotbeta-cotalpha))/(cos(alpha+beta))`

`(h(cotalpha-cotbeta)`

`(h(tanbeta-tanalpha))/(tanalphatanbeta)`

`h(cotalpha+cotbeta)`

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The angle of elevation of the top of a tower standing on a horizontal plane from two on a line passing through the foot of the tower at a distance 9 ft and 16 ft respectively are complementary angles. Then the height of the tower is:

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The angle of elevation of the top of a tower standing on a horizontal plane from a point A is alpha . After walking a distance d towards the foot of the tower the angle of elevation is found to be beta . The height of the tower is (a)d/(cotalpha+cotbeta) (b) d/(cotalpha-cotbeta) (c)d/(tanbeta-t a nalpha) (d) d/(tanbeta+tanalpha)

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