`1 g of H_(2)O` changes from liquid to vapour phase at constant pressure at `1 atm`. The pressure increases from `1 cc to 1671 cc`. The heat of vaporization at this pressure is `540 cal//g`. The increase in internal energy of water is

When 1 gm of water changes from liquid to vapour phase at constant pressures of 1 atmosphere, the volume increases from 1 cc to 1671 cc. The heat of vaporisation at this pressure is 540 cal/gm. Increase in internal in internal energy of water is (1 atmosphere = 1.01xx10^(6) "dyne/cm"^(2))

When 1 gm of water changes from liquid to vapour phase at constant pressure of 1 atmosphre, the volume increases from 1cc to 1671cc. The heat of vaporisation at his pressure is 540 cal/gm. Increase in internal energy of water is (1 atmosphre =1.01x 10^(6) dyne/ cm^(2) )

1g of water changes from liquid to vapour phase at constant pressure of 1 atmosphere, the volume increases from 1 mL to 1671 mL . The heat of vaporisation at this pressure is 540 cal//g . Find the: (a) Work done (in J )during phase change. (b) Increase in internal energy of water.

One gram of water (1 cm^(3)) becomes 1671 cm^(3) of steam at a pressure of 1 atm. The latent heat of vaporization at this pressure is 2256 J/g. Calculate the external work and the increase in internal energy.

If the pressure of a gas at constant volume changes from 2 atm to 1 atm. The temperature changes from 0^@C

1 g of water in liquid phase has volume 1 cm^(3) and in vapour phase 1671 cm^(3) at atmospheric pressure and the latent heat of vaporization of water is 2256 J/g, the change in the internal energy in joules for 1 g of water of 373K when it changes from liquid phase to vapour phase at the same temperature is: