Home
Class 14
REASONING
JKPO : LMNM : : ? : PQJI (a) KOLN (b) ...

JKPO : LMNM : : ? : PQJI (a) KOLN (b) LKNO (c) NOLK (d) NOKL

A

KOLN

B

LKNO

C

NOLK

D

NOKL

Text Solution

Verified by Experts

The correct Answer is:
C

Promotional Banner

Topper's Solved these Questions

  • ANALOGY OR SIMILARITY

    KIRAN PUBLICATION|Exercise TYPE-IV (Select the related letter from the given alternatives.)|230 Videos
  • ANALOGY OR SIMILARITY

    KIRAN PUBLICATION|Exercise TYPE-V|37 Videos
  • ANALOGY OR SIMILARITY

    KIRAN PUBLICATION|Exercise TYPE-III|373 Videos
  • ARRANGEMENT OF WORDS IN LOGICAL ORDER

    KIRAN PUBLICATION|Exercise TYPE II|199 Videos

Similar Questions

Explore conceptually related problems

In an equilateral triangle A B C if A D_|_B C , then A D^2 = (a)C D^2 (b) 2C D^2 (c) 3C D^2 (d) 4C D^2

Write increasing order of basic strength of following: (i). (a) F^(ɵ) , (b). Cl^(ɵ) , (c). Br^(ɵ) , (d). I^(ɵ) (A). a gt b gt c gt d (B). d lt a lt c lt b (C). d gt a gt b gt c (D). a gt d gt c gt b (ii). (a). CH_(3)^(ɵ) , (b). Cl^(ɵ) , (c) OH^(ɵ) , (d). F^(ɵ) (A). a gt b gt c gt d (B). d lt a lt c lt b (C). d gt a gt b gt c (D). a gt d gt c gt b (iii). (a). R-NH_(2) , (b). Ph-NH_(2) , (c). R-underset(O)underset(||)(C)-NH_(2) (A). a gt b gt c (B). a lt c lt b (C). a lt b lt c (D). a gt c gt b (iv). (a). NH_(3) , (b). MeNH_(2) , (c). Me_(2)NH , (d). Me_(2)N (A). a lt b lt c lt d (B). d lt a lt c lt b (C). d gt a gt b gt c (D). a gt d gt c gt b

Let a,b,c,d,A,B,C,D in R . If A/a = B/b = C/c = D/d then (sqrt(Aa) + sqrt(Bb) + sqrt(Cc) + sqrt(Dd)) / (sqrt(a+b+c+d) sqrt(A+B+C+D))=

If (a+b)/(b+c)=(c+d)/(d+a) , then

If (a+b+2c+3d)(a-b-2c+3d)=(a-b+2c-3d)(a+b-2c-3d) , then 2b c is equal to 3/2 (b) (3a)/(2d) (c) 3a d (d) a^2d^2

Given a set A = {a, b, c, d}, then the relation: R={(a,a),(b,b),(c,c),(d,d)} is reflexive?.

When two ratios are equal, then the four quantities compositing them are said to be proportiona. If a/b=c/d, then it is written a:b=c:dor a:b::c:d. Also if a/b=c/d=lamdaimpliesa=blamdaand c=dlamdaimpliesa/b=c/d =(a+-c)/(b+-d)=(""^(n)sqrt((a)^(n)+-(c)^(n)))/(""^(n)sqrt((b)^(n)+-(d)^(n)))=lamda(lamdagt0) important property of proportion : 1. If a:b=c:d,then (a+b)/(b)=(c+d)/(d)("Componendo")i.e.(a)/(b)=(c)/(d)implies(a)/(b)+1=(c)/(d)+1 2. If a:b=c"d, then (a-b)/(b)=(c-d)/(d)("Dividenod")i.e.(a)/(b)=(c)/(d)implies(a)/(b)-1=(c)/(d)-1 3. If a:b:=c:d, then (a+b)/(a-b)=(c+d)/(c-d)("Componendo and dividendo") If a/b=c/d=e/fand(2a^(4)b^(2)+3a^(2)c^(2)-5e^(4)f)/(2b^(6)+3b^(2)d^(2)-5f^(5))=((a)/(b))^(n) then teh value of n is :

If (a)/(b)=(b)/(c)=(c)/(d), then (b^(3)+c^(3)+d^(3))/(a^(3)+b^(3)+c^(3)) will be equal to (a)/(b) b.(b)/(c) c.(c)/(d) d.(d)/(a)