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REASONING
a=23(529)(1024), b=21(441)(144), c=1...

`a=23(529)(1024)`,
`b=21(441)(144)`,
`c=19(361)(?)`

A

1441

B

3529

C

9361

D

8281

Text Solution

Verified by Experts

The correct Answer is:
D
`a=23(529)(1024)`
The second number is the square of the first number and the third number is the square of that number obtained by interchanging the digits of the first number.
Thus, `(23)^(2)=23xx32=1024`
`rArrb=21 (441) (144)`
`(21)^(2)=21xx21=441`
`(12)^(2)=12xx12=144`
similarly,
`c=19 (361) (?)`
`(19)^(2)=19xx19=361`
`(91)^(2)=91xx91=8281`
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