If the present population of a town is 72600 and it is decreased by 10 % per annum what will be its population 2 years hence ?

Answer

To solve the problem of determining the population of a town after a decrease of 10% per annum over 2 years, we can follow these steps:

### Step 1: Understand the decrease in population
The current population of the town is 72,600. Each year, the population decreases by 10%. This means that at the end of each year, 90% of the population remains.

### Step 2: Calculate the remaining population after 1 year
To find the population after 1 year, we can calculate:
\[ \text{Population after 1 year} = \text{Current Population} \times (1 - \text{decrease rate}) \]
\[ \text{Population after 1 year} = 72600 \times (1 - 0.10) = 72600 \times 0.90 \]
\[ \text{Population after 1 year} = 72600 \times 0.90 = 65340 \]

### Step 3: Calculate the remaining population after 2 years
Now, we need to calculate the population after the second year using the population after the first year:
\[ \text{Population after 2 years} = \text{Population after 1 year} \times (1 - \text{decrease rate}) \]
\[ \text{Population after 2 years} = 65340 \times (1 - 0.10) = 65340 \times 0.90 \]
\[ \text{Population after 2 years} = 65340 \times 0.90 = 58806 \]

### Final Answer
The population of the town after 2 years will be **58,806**.

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