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The S.I. occured on a sum of money at th...

The S.I. occured on a sum of money at the rate of interest 5% per annum for two years. Is 410 Rs. The compound interest is the same as S.I as occured on other sum of money at the same rate of interest and the same time. Find the difference between the two sum of money (principle) ?

A

Rs. 80

B

Rs. 90

C

Rs. 150

D

None of these

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The correct Answer is:
To solve the problem step by step, we will first calculate the principal amount based on the simple interest (S.I.) given, and then we will find the principal amount for the compound interest (C.I.) before determining the difference between the two principal amounts. ### Step 1: Understand the Simple Interest Formula The formula for Simple Interest (S.I.) is: \[ \text{S.I.} = \frac{P \times R \times T}{100} \] Where: - \( P \) = Principal amount - \( R \) = Rate of interest per annum - \( T \) = Time in years ### Step 2: Substitute the Known Values for S.I. From the question, we know: - S.I. = 410 Rs. - R = 5% per annum - T = 2 years Substituting these values into the S.I. formula gives: \[ 410 = \frac{P \times 5 \times 2}{100} \] ### Step 3: Solve for Principal (P) Rearranging the equation to find \( P \): \[ 410 = \frac{10P}{100} \] \[ 410 = \frac{P}{10} \] \[ P = 410 \times 10 = 4100 \text{ Rs.} \] ### Step 4: Calculate the Compound Interest For Compound Interest (C.I.), the formula is: \[ \text{C.I.} = P \left(1 + \frac{R}{100}\right)^T - P \] Using the same principal amount \( P \) as calculated for S.I.: \[ \text{C.I.} = P \left(1 + \frac{5}{100}\right)^2 - P \] \[ = P \left(1 + 0.05\right)^2 - P \] \[ = P \left(1.05\right)^2 - P \] \[ = P \times 1.1025 - P \] \[ = P \times (1.1025 - 1) \] \[ = P \times 0.1025 \] ### Step 5: Set C.I. Equal to S.I. Since the C.I. is equal to the S.I. of another sum of money, we set: \[ P \times 0.1025 = 410 \] Substituting \( P = 4100 \): \[ 4100 \times 0.1025 = 410 \] ### Step 6: Find the Principal for C.I. Let’s denote the principal for C.I. as \( P' \): \[ P' \times 0.1025 = 410 \] \[ P' = \frac{410}{0.1025} = 4000 \text{ Rs.} \] ### Step 7: Calculate the Difference Between the Two Principals Now, we find the difference between the two principal amounts: \[ \text{Difference} = P - P' = 4100 - 4000 = 100 \text{ Rs.} \] ### Final Answer The difference between the two sums of money (principals) is **100 Rs.**.
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MAHENDRA-SIMPLE INTEREST & COMPOUND INTEREST-EXERCISE
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  6. What will be the compound interest on a sum of Rs. 25,000 after 3 year...

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  10. Find the compound interest on Rs. 15625 for 9 months at 16% per annum ...

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  12. If the compound interest on a sum for 2 years at 12(1)/2% per annum i...

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  13. The compound interest on a certain sum for 2 years at 10% per annum i...

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  14. The simple interest on a certain sum of money for 3 years at 8% per an...

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  15. There is 60% increase in an amount in 6 years at the rate of simple in...

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  16. Sum of money invested at compound interest amounts to Rs. 4624 in 2 ye...

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  17. A sum of money placed at compound interest doubles itself in 5 years. ...

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  18. Durgesh borrowed an amount of Rs. 15,000 at the simple interest rate o...

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  19. 2100 is divided into two parts such that the simple interest on the on...

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  20. The S.I. occured on a sum of money at the rate of interest 5% per annu...

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