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A train travelling at 36 km/hr. complete...

A train travelling at 36 km/hr. completely crosses another train having half its length and travelling in the opposite direction at 54 km/hr. in 12 seconds. If it also passes a railway plat form in `1(1)/(2)` minutes, the length of the platform is:

A

740 metres

B

700 metres

C

620 metres

D

560 metres

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The correct Answer is:
To solve the problem step by step, we will follow the reasoning provided in the video transcript. ### Step 1: Understand the Problem We have two trains moving in opposite directions. The first train travels at 36 km/hr and the second train travels at 54 km/hr. The first train completely crosses the second train in 12 seconds. We need to find the length of a platform that the first train crosses in 1.5 minutes. ### Step 2: Convert Speeds to Meter per Second To work with the speeds in a more manageable unit (meters per second), we convert the speeds from kilometers per hour to meters per second using the conversion factor \( \frac{5}{18} \). - Speed of the first train: \[ 36 \text{ km/hr} = 36 \times \frac{5}{18} = 10 \text{ m/s} \] - Speed of the second train: \[ 54 \text{ km/hr} = 54 \times \frac{5}{18} = 15 \text{ m/s} \] ### Step 3: Calculate the Relative Speed Since the trains are moving in opposite directions, we add their speeds to find the relative speed: \[ \text{Relative Speed} = 10 \text{ m/s} + 15 \text{ m/s} = 25 \text{ m/s} \] ### Step 4: Set Up the Equation for Crossing the Second Train Let the length of the first train be \( 2x \) and the length of the second train be \( x \) (since it is half the length of the first train). The total distance covered when the first train crosses the second train is: \[ \text{Distance} = 2x + x = 3x \] Using the formula for time, which is: \[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \] We can set up the equation: \[ 12 \text{ seconds} = \frac{3x}{25} \] ### Step 5: Solve for \( x \) Rearranging the equation gives: \[ 3x = 12 \times 25 \] \[ 3x = 300 \] \[ x = 100 \text{ meters} \] Thus, the length of the first train is: \[ 2x = 2 \times 100 = 200 \text{ meters} \] ### Step 6: Calculate the Time Taken to Cross the Platform The first train crosses a platform in 1.5 minutes. Converting this time to seconds: \[ 1.5 \text{ minutes} = 1.5 \times 60 = 90 \text{ seconds} \] ### Step 7: Calculate the Distance Covered While Crossing the Platform Using the speed of the first train (which is 10 m/s), we can find the total distance covered while crossing the platform: \[ \text{Distance} = \text{Speed} \times \text{Time} = 10 \text{ m/s} \times 90 \text{ s} = 900 \text{ meters} \] ### Step 8: Find the Length of the Platform The distance covered while crossing the platform is the sum of the lengths of the first train and the platform: \[ \text{Distance} = \text{Length of the first train} + \text{Length of the platform} \] Thus, \[ 900 = 200 + \text{Length of the platform} \] Solving for the length of the platform gives: \[ \text{Length of the platform} = 900 - 200 = 700 \text{ meters} \] ### Final Answer The length of the platform is **700 meters**. ---
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