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A marchant has 50 kg. of sugar, part of ...

A marchant has 50 kg. of sugar, part of which he sells at 8% profit and the rest at 18% profit, He gains 14% on the whole. The quantity sold at 18% profit is:

A

20 kg

B

30 kg

C

15 kg

D

35 kg

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AI Generated Solution

The correct Answer is:
To solve the problem step by step, we can use the method of alligation. Here’s how to approach it: ### Step 1: Understand the given information We have a total of 50 kg of sugar. The merchant sells part of it at an 8% profit and the rest at an 18% profit. The overall profit from selling all the sugar is 14%. ### Step 2: Set up the alligation We will use alligation to find the ratio of the quantities sold at different profit percentages. The profits are: - Profit 1 (P1) = 8% - Profit 2 (P2) = 18% - Overall Profit (P) = 14% ### Step 3: Calculate the differences Now, we calculate the differences between the overall profit and the individual profits: - Difference between P and P1: \( 14 - 8 = 6 \) - Difference between P2 and P: \( 18 - 14 = 4 \) ### Step 4: Set up the ratio Using the differences calculated, we can set up the ratio of the quantities sold at each profit: - The ratio of the quantities sold at 8% profit to the quantities sold at 18% profit is given by the differences: \[ \text{Ratio} = \frac{6}{4} = \frac{3}{2} \] ### Step 5: Determine the total parts The total parts in the ratio are \( 3 + 2 = 5 \). ### Step 6: Calculate the quantity corresponding to each part Now, we know that the total quantity of sugar is 50 kg. We can find the value of one part: \[ \text{Value of one part} = \frac{50 \text{ kg}}{5} = 10 \text{ kg} \] ### Step 7: Calculate the quantity sold at 18% profit Since the ratio of the quantity sold at 8% profit to that sold at 18% profit is 3:2, the quantity sold at 18% profit corresponds to 2 parts: \[ \text{Quantity sold at 18% profit} = 2 \times 10 \text{ kg} = 20 \text{ kg} \] ### Final Answer The quantity sold at 18% profit is **20 kg**. ---
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