In the following questions two equation numbered I and II are given You have to solve both equations and . . . . .
(i) `225x^(2)-4=0`
(ii) `sqrt(225y)+2=0`

Answer

To solve the given equations, we will follow these steps:

### Step 1: Solve Equation I
The first equation is:
\[ 225x^2 - 4 = 0 \]

**Solution:**
1. Rearrange the equation:
\[ 225x^2 = 4 \]

2. Divide both sides by 225:
\[ x^2 = \frac{4}{225} \]

3. Take the square root of both sides:
\[ x = \pm \sqrt{\frac{4}{225}} \]

4. Simplify the square root:
\[ x = \pm \frac{2}{15} \]

### Step 2: Solve Equation II
The second equation is:
\[ \sqrt{225y} + 2 = 0 \]

**Solution:**
1. Rearrange the equation:
\[ \sqrt{225y} = -2 \]

2. Since the square root cannot be negative, we conclude that there are no real solutions for this equation.

### Final Answers:
- From Equation I, we have:
\[ x = \frac{2}{15} \text{ or } x = -\frac{2}{15} \]

- From Equation II, there are no real solutions for \( y \).

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