In the following questions two equation numbered I and II are given You have to solve both equations and . . . . .
(i) `x^(2)=16=0`
(ii) `y^(2)-9y+20=0`

Answer

Let's solve the given equations step by step.

### Step 1: Solve the first equation \( x^2 = 16 \)

1. Rewrite the equation:
\[ x^2 = 16 \]

2. Take the square root of both sides:
\[ x = \pm \sqrt{16} \]

3. Calculate the square root:
\[ x = \pm 4 \]

### Step 2: Solve the second equation \( y^2 - 9y + 20 = 0 \)

1. Rewrite the equation:
\[ y^2 - 9y + 20 = 0 \]

2. Factor the quadratic equation. We need two numbers that multiply to 20 and add up to -9. The numbers are -4 and -5:
\[ (y - 4)(y - 5) = 0 \]

3. Set each factor to zero:
\[ y - 4 = 0 \quad \text{or} \quad y - 5 = 0 \]

4. Solve for \( y \):
\[ y = 4 \quad \text{or} \quad y = 5 \]

### Final Solutions

- From the first equation, we have \( x = 4 \) and \( x = -4 \).
- From the second equation, we have \( y = 4 \) and \( y = 5 \).

### Summary of Solutions:
- \( x = 4 \) or \( x = -4 \)
- \( y = 4 \) or \( y = 5 \)

---