In each of the following questions, two equations are given. You have to solve them and give answer(निम्नलिखित प्रत्येक प्रश्न में दो समीकरण दिए गए हैं। आपको उन्हें हल करना है और उत्तर देना है
I. `x+(1)/2 =3 `
II. `y+13div 2 = 6(y-1)`

Options

A. `xgty`
B. `xgey`
C. `x lty`
D. x = y or relationship can not be established(x = y या संबंध स्थापित नहीं किया जा सकता)

Answer

To solve the given equations step by step, we will first tackle each equation separately.

### Step 1: Solve the first equation
The first equation is:
\[ x + \frac{1}{2} = 3 \]

To isolate \( x \), we will subtract \( \frac{1}{2} \) from both sides:
\[ x = 3 - \frac{1}{2} \]

Now, we need to perform the subtraction:
Convert \( 3 \) into a fraction:
\[ 3 = \frac{6}{2} \]
So, we have:
\[ x = \frac{6}{2} - \frac{1}{2} \]
\[ x = \frac{6 - 1}{2} = \frac{5}{2} \]

### Step 2: Solve the second equation
The second equation is:
\[ y + \frac{13}{2} = 6(y - 1) \]

First, expand the right side:
\[ y + \frac{13}{2} = 6y - 6 \]

Next, we will move \( y \) to the right side by subtracting \( y \) from both sides:
\[ \frac{13}{2} = 6y - y - 6 \]
\[ \frac{13}{2} = 5y - 6 \]

Now, add \( 6 \) to both sides. To do this, convert \( 6 \) into a fraction:
\[ 6 = \frac{12}{2} \]
So:
\[ \frac{13}{2} + \frac{12}{2} = 5y \]
\[ \frac{25}{2} = 5y \]

Now, divide both sides by \( 5 \):
\[ y = \frac{25}{2} \div 5 = \frac{25}{2} \times \frac{1}{5} = \frac{25}{10} = \frac{5}{2} \]

### Step 3: Compare the values of \( x \) and \( y \)
From our calculations, we found:
\[ x = \frac{5}{2} \]
\[ y = \frac{5}{2} \]

Since both \( x \) and \( y \) are equal, we conclude:
\[ x = y \]

### Final Answer
The relation between \( x \) and \( y \) is:
\[ x \text{ is equal to } y \]