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Radhika invested an amount of Rs. 6000 f...

Radhika invested an amount of Rs. 6000 for 2 years. At what rate of compound interest will she get compound interest of Rs. 615 at the end of two year ?

A

3 p.c.p.a

B

4 p.c.p.a

C

6 p.c.p.a

D

5 p.c.p.a

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The correct Answer is:
To find the rate of compound interest at which Radhika will earn a compound interest of Rs. 615 after 2 years on an investment of Rs. 6000, we can follow these steps: ### Step 1: Calculate the Total Amount First, we need to calculate the total amount after 2 years, which is the principal plus the compound interest. \[ \text{Total Amount} = \text{Principal} + \text{Compound Interest} = 6000 + 615 = 6615 \] ### Step 2: Use the Compound Interest Formula The formula for the amount \( A \) in compound interest is: \[ A = P \left(1 + \frac{r}{100}\right)^n \] Where: - \( A \) = Total Amount - \( P \) = Principal - \( r \) = Rate of interest - \( n \) = Number of years Substituting the known values into the formula: \[ 6615 = 6000 \left(1 + \frac{r}{100}\right)^2 \] ### Step 3: Simplify the Equation To isolate the term with \( r \), we divide both sides by 6000: \[ \frac{6615}{6000} = \left(1 + \frac{r}{100}\right)^2 \] Calculating the left side: \[ \frac{6615}{6000} = 1.1025 \] So, we have: \[ 1.1025 = \left(1 + \frac{r}{100}\right)^2 \] ### Step 4: Take the Square Root Next, we take the square root of both sides to solve for \( 1 + \frac{r}{100} \): \[ \sqrt{1.1025} = 1 + \frac{r}{100} \] Calculating the square root: \[ 1 + \frac{r}{100} = 1.05 \] ### Step 5: Solve for \( r \) Now, we can isolate \( r \): \[ \frac{r}{100} = 1.05 - 1 = 0.05 \] Multiplying both sides by 100 gives us: \[ r = 0.05 \times 100 = 5 \] ### Conclusion Thus, the rate of compound interest \( r \) is: \[ \boxed{5\%} \] ---
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