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What approximate value will come in plac...

What approximate value will come in place of questions mark (?) in the following questions?
`(787)/(32)-:(55)/(869)xx(415)/(207)=?`

A

800

B

760

C

780

D

750

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \((787)/(32) - (55)/(869) \times (415)/(207) = ?\), we will approximate the values step by step. ### Step 1: Approximate the fractions We will approximate each fraction to make calculations easier. 1. **Approximate \( \frac{787}{32} \)**: - \( 787 \approx 800 \) (since 787 is close to 800) - \( 32 \approx 30 \) (since 32 is close to 30) - So, \( \frac{787}{32} \approx \frac{800}{30} \approx \frac{80}{3} \approx 26.67 \) 2. **Approximate \( \frac{55}{869} \)**: - \( 55 \approx 50 \) (rounding down) - \( 869 \approx 900 \) (rounding up) - So, \( \frac{55}{869} \approx \frac{50}{900} \approx \frac{1}{18} \approx 0.055 \) 3. **Approximate \( \frac{415}{207} \)**: - \( 415 \approx 400 \) (rounding down) - \( 207 \approx 200 \) (rounding down) - So, \( \frac{415}{207} \approx \frac{400}{200} = 2 \) ### Step 2: Substitute approximations into the expression Now we substitute the approximated values back into the expression: \[ \frac{787}{32} - \left(\frac{55}{869} \times \frac{415}{207}\right) \approx 26.67 - (0.055 \times 2) \] ### Step 3: Calculate the multiplication Now, calculate \( 0.055 \times 2 \): \[ 0.055 \times 2 \approx 0.11 \] ### Step 4: Final calculation Now, substitute this back into the expression: \[ 26.67 - 0.11 \approx 26.56 \] ### Step 5: Convert to a more manageable number Since we are looking for an approximate value in a larger scale, we can multiply by 1000 to convert our result: \[ 26.56 \times 1000 \approx 765.6 \] ### Step 6: Choose the closest option Looking at the options provided: - Option A: 800 - Option B: 760 - Option C: 780 - Option D: 750 The closest approximation to 765.6 is **Option B: 760**. ### Final Answer: The approximate value that will come in place of the question mark (?) is **760**. ---
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