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What will come in the place of question ...

What will come in the place of question mark (?) in following questions?
`5(6)/(7) + 8(2)/(14)+9(1)/(7)`= ?

A

`22(3)/(7)`

B

`23(1)/(7)`

C

`24(2)/(7)`

D

`26(1)/(14)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \(5\frac{6}{7} + 8\frac{2}{14} + 9\frac{1}{7}\), we will follow these steps: ### Step 1: Convert Mixed Numbers to Improper Fractions First, we need to convert each mixed number into an improper fraction. 1. For \(5\frac{6}{7}\): \[ 5\frac{6}{7} = \frac{5 \times 7 + 6}{7} = \frac{35 + 6}{7} = \frac{41}{7} \] 2. For \(8\frac{2}{14}\): \[ 8\frac{2}{14} = \frac{8 \times 14 + 2}{14} = \frac{112 + 2}{14} = \frac{114}{14} \] We can simplify \(\frac{114}{14}\) by dividing both the numerator and denominator by 2: \[ \frac{114 \div 2}{14 \div 2} = \frac{57}{7} \] 3. For \(9\frac{1}{7}\): \[ 9\frac{1}{7} = \frac{9 \times 7 + 1}{7} = \frac{63 + 1}{7} = \frac{64}{7} \] ### Step 2: Add the Improper Fractions Now we can add the three improper fractions: \[ \frac{41}{7} + \frac{57}{7} + \frac{64}{7} \] Since they have the same denominator, we can simply add the numerators: \[ \frac{41 + 57 + 64}{7} = \frac{162}{7} \] ### Step 3: Convert the Improper Fraction Back to a Mixed Number To convert \(\frac{162}{7}\) back to a mixed number: 1. Divide 162 by 7: \[ 162 \div 7 = 23 \quad \text{(whole number)} \] The remainder is: \[ 162 - (23 \times 7) = 162 - 161 = 1 \] Thus, we can express it as: \[ 23\frac{1}{7} \] ### Final Answer The answer to the expression \(5\frac{6}{7} + 8\frac{2}{14} + 9\frac{1}{7}\) is: \[ \boxed{23\frac{1}{7}} \]
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