In an examination it is required to get 352 of the aggregate marks to pass. A student gets 264 marks and is declared failed by 10% marks What is the maximum aggregate marks a student can get?

Options

A. 825
B. 850
C. 890
D. None of these

Answer

To solve the problem step by step, we can follow these instructions:

### Step 1: Identify the required passing marks and the marks obtained by the student.
- The required passing marks = 352
- Marks obtained by the student = 264

### Step 2: Calculate the difference between the required passing marks and the marks obtained.
- Difference = Required passing marks - Marks obtained
- Difference = 352 - 264 = 88

### Step 3: Understand the meaning of "failed by 10% marks".
- The student failed by 10% of the maximum aggregate marks. This means that the difference of 88 marks is equal to 10% of the maximum marks.

### Step 4: Let the maximum aggregate marks be denoted as 'x'.
- According to the information given, we can set up the equation:
\[ 10\% \text{ of } x = 88 \]

### Step 5: Convert the percentage into a decimal for calculation.
- 10% can be expressed as 0.1. Therefore, we can rewrite the equation as:
\[ 0.1x = 88 \]

### Step 6: Solve for x (maximum aggregate marks).
- To find x, divide both sides of the equation by 0.1:
\[ x = \frac{88}{0.1} = 880 \]

### Step 7: Conclusion
- The maximum aggregate marks a student can get is **880**.

---