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((?)^(1.8))/(72) = (24)/((?)^(1.2))...

`((?)^(1.8))/(72) = (24)/((?)^(1.2))`

A

8

B

14

C

6

D

12

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The correct Answer is:
To solve the equation \(\frac{(x)^{1.8}}{72} = \frac{24}{(x)^{1.2}}\), we will follow these steps: ### Step 1: Cross-Multiply We start by cross-multiplying to eliminate the fractions. This gives us: \[ (x)^{1.8} \cdot (x)^{1.2} = 24 \cdot 72 \] ### Step 2: Combine Exponents Using the property of exponents that states \(a^m \cdot a^n = a^{m+n}\), we can combine the left side: \[ (x)^{1.8 + 1.2} = 24 \cdot 72 \] This simplifies to: \[ (x)^{3.0} = 24 \cdot 72 \] ### Step 3: Calculate the Right Side Now we calculate \(24 \cdot 72\): \[ 24 \cdot 72 = 1728 \] So, we have: \[ (x)^3 = 1728 \] ### Step 4: Solve for \(x\) To find \(x\), we take the cube root of both sides: \[ x = \sqrt[3]{1728} \] ### Step 5: Calculate the Cube Root Now we calculate the cube root of \(1728\): \[ \sqrt[3]{1728} = 12 \] Thus, the value of the question mark \(x\) is: \[ \boxed{12} \]
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Pipes A, B and C can fill an empty tank in 12 minutes, 24 minutes and 36 minutes respectively. Pipes D and E can empty the full tank in 18 minutes and 72 minutes respectively. If all of them are opened simultaneously, then find the time taken to fill the empty tank. The following are the steps involved in solving the above problem. Arrange them in sequential order. (11)/(72)-(5)/(72)=(6)/(72)=(1)/(12) The work done by 5 pipes in1 minute. =((1)/(12)+(1)/(24)+(1)/(36))-((1)/(18)+(1)/(72)) ((6+3+2)/(72))-((4+1)/(72)) The part of tank filled by A,B and C in 1 minute is 1/12,1/24 and 1/36 respectively. The part of the tank emptied by D and E in 1 minute is 1/18 and 1/72 respectively.

Pipes A, B and C can fill an empty tank in 12 minutes, 24 minutes and 36 minutes respectively. Pipes D and E can empty the full tank in 18 minutes and 72 minutes respectively. If all of them are opened simultaneously, then find the time taken to fill the empty tank. The following are the steps involved in solving the above problem. Arrange them in sequential order. (11)/(72)-(5)/(72)=(6)/(72)=(1)/(12) The work done by 5 pipes in1 minute. =((1)/(12)+(1)/(24)+(1)/(36))-((1)/(18)+(1)/(72)) ((6+3+2)/(72))-((4+1)/(72)) The part of tank filled by A,B and C in 1 minute is 1/12,1/24 and 1/36 respectively. The part of the tank emptied by D and E in 1 minute is 1/18 and 1/72 respectively.

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