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A shopkeeper sold a TV a 16% discount on...

A shopkeeper sold a TV a 16% discount on print rate. If the customer is paid Rs. 9828 for the TV and the printed price is 20% more than its cost price, what is the cost price of TV ?

A

Rs. 9875

B

Rs. 9450

C

Rs. 9750

D

Rs. 9850

Text Solution

AI Generated Solution

The correct Answer is:
To find the cost price of the TV, we can follow these steps: ### Step 1: Define Variables Let the cost price (CP) of the TV be \( x \). ### Step 2: Calculate the Marked Price (MP) The marked price is 20% more than the cost price. Therefore, we can express the marked price as: \[ MP = CP + 20\% \text{ of } CP = x + 0.2x = 1.2x \] ### Step 3: Calculate the Selling Price (SP) The shopkeeper sold the TV at a 16% discount on the marked price. The selling price can be calculated as: \[ SP = MP - 16\% \text{ of } MP = MP - 0.16 \times MP = MP \times (1 - 0.16) = MP \times 0.84 \] Substituting the expression for MP: \[ SP = 0.84 \times (1.2x) = 1.008x \] ### Step 4: Set Up the Equation According to the problem, the selling price is Rs. 9828. Therefore, we can set up the equation: \[ 1.008x = 9828 \] ### Step 5: Solve for x To find the cost price, we can solve for \( x \): \[ x = \frac{9828}{1.008} \] Calculating this gives: \[ x = 9748.81 \approx 9750 \text{ (rounding to the nearest whole number)} \] ### Step 6: Calculate the Cost Price Since we defined \( x \) as the cost price, we conclude that: \[ CP = 9750 \] ### Final Answer The cost price of the TV is Rs. 9750. ---
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