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What should come in place of the questio...

What should come in place of the question mark (?) in the following questions:
`4 (1)/(3) + 3 (1)/(4) - 1 (1)/(12) = ?`

A

`6 1/2`

B

`6 5/12`

C

`4 1/2`

D

`1 1/12`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \( 4 \frac{1}{3} + 3 \frac{1}{4} - 1 \frac{1}{12} = ? \), we will follow these steps: ### Step 1: Convert Mixed Numbers to Improper Fractions First, we convert the mixed numbers into improper fractions. - For \( 4 \frac{1}{3} \): \[ 4 \frac{1}{3} = \frac{4 \times 3 + 1}{3} = \frac{12 + 1}{3} = \frac{13}{3} \] - For \( 3 \frac{1}{4} \): \[ 3 \frac{1}{4} = \frac{3 \times 4 + 1}{4} = \frac{12 + 1}{4} = \frac{13}{4} \] - For \( 1 \frac{1}{12} \): \[ 1 \frac{1}{12} = \frac{1 \times 12 + 1}{12} = \frac{12 + 1}{12} = \frac{13}{12} \] ### Step 2: Rewrite the Equation Now we can rewrite the equation using the improper fractions: \[ \frac{13}{3} + \frac{13}{4} - \frac{13}{12} = ? \] ### Step 3: Find the Least Common Multiple (LCM) Next, we need to find the LCM of the denominators (3, 4, and 12). The LCM is 12. ### Step 4: Convert Each Fraction to Have a Common Denominator Now we convert each fraction to have a denominator of 12: - For \( \frac{13}{3} \): \[ \frac{13}{3} = \frac{13 \times 4}{3 \times 4} = \frac{52}{12} \] - For \( \frac{13}{4} \): \[ \frac{13}{4} = \frac{13 \times 3}{4 \times 3} = \frac{39}{12} \] - For \( \frac{13}{12} \): \[ \frac{13}{12} = \frac{13}{12} \quad (\text{remains the same}) \] ### Step 5: Substitute Back into the Equation Now we can substitute these back into the equation: \[ \frac{52}{12} + \frac{39}{12} - \frac{13}{12} \] ### Step 6: Combine the Fractions Combine the fractions: \[ \frac{52 + 39 - 13}{12} = \frac{78}{12} \] ### Step 7: Simplify the Result Now simplify \( \frac{78}{12} \): \[ \frac{78 \div 6}{12 \div 6} = \frac{13}{2} \] ### Step 8: Convert Back to Mixed Number Convert \( \frac{13}{2} \) back to a mixed number: \[ \frac{13}{2} = 6 \frac{1}{2} \] Thus, the final answer is: \[ ? = 6 \frac{1}{2} \]
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