A cubical block (of sie 2m) of mass 20 kg slides on inclined plane lubricated with the oil of viscosity `eta=10^(-1)` poise with constant velocity of 10 m/s find out the thickness of layer of liquid (`g=10m//s^(2)`)

A cubical block (of side 2 m ) of mass 20 kg slides on inclined plane lubricated with the oil of viscosity eta=10^(-1) with constant velocity of 10 ms^(-1) . Find out the thickness of the layer of liquid (take g = 10 ms^(-2) ).

A cubical block (of side 2 m ) of mass 20 kg slides on inclined plane lubricated with the oil of viscosity eta=10^(-1) with constant velocity of 10 ms^(-1) . Find out the thickness of the layer of liquid (take g = 10 ms^(-2) ).

A block of mass 2 kg rests on an inclined plane of inclination angle 37^(@) , then calculate the force of friction acting on the block [ take g = 10 m//s^(2))

Block of mass 10 kg is moving on inclined plane with constant velocity 10 m/s. The coedfficient of kinetic friction between incline plane and block is :-

Block of mass 10 kg is moving on inclined plane with constant velocity 10 m/s. The coedfficient of kinetic friction between incline plane and block is :-

Block of mass 10 kg is moving on inclined plane with constant velocity 10 m/s. The coedfficient of kinetic friction between incline plane and block is :-

An external force 6N is applied on a sphere of radius R = 10 cm of mass 1 kg and the sphere moves in a liquid with a constant velocity 5 m/s making 530 with the horizontal.The coefficient of viscosity of the liquid is 20//(6pi), in S.I units. (Take g=10 m//s^(2) )

An external force 6N is applied on a sphere of radius R = 10 cm of mass 1 kg and the sphere moves in a liquid with a constant velocity 5 m/s making 530 with the horizontal.The coefficient of viscosity of the liquid is 20//(6pi), in S.I units. (Take g=10 m//s^(2) )

A mass of 1 kg is just able to slide down the slope of an inclined rough surface when the angle of inclination is 60^(@) The minima force necessary to pull the mass up the inclined plane is: (g=10 m//s^(2))