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Value of (3+sqrt6)/(5sqrt3-2sqrt12-sqrt3...

Value of `(3+sqrt6)/(5sqrt3-2sqrt12-sqrt32+sqrt50)` is

A

`1/sqrt3`

B

`sqrt3`

C

`1/3`

D

3

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The correct Answer is:
To solve the expression \(\frac{3+\sqrt{6}}{5\sqrt{3}-2\sqrt{12}-\sqrt{32}+\sqrt{50}}\), we will simplify the denominator first and then rationalize the fraction. ### Step 1: Simplify the Denominator The denominator is \(5\sqrt{3} - 2\sqrt{12} - \sqrt{32} + \sqrt{50}\). 1. **Simplify \(\sqrt{12}\)**: \[ \sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \cdot \sqrt{3} = 2\sqrt{3} \] Therefore, \(-2\sqrt{12} = -2 \cdot 2\sqrt{3} = -4\sqrt{3}\). 2. **Simplify \(\sqrt{32}\)**: \[ \sqrt{32} = \sqrt{16 \times 2} = \sqrt{16} \cdot \sqrt{2} = 4\sqrt{2} \] Therefore, \(-\sqrt{32} = -4\sqrt{2}\). 3. **Simplify \(\sqrt{50}\)**: \[ \sqrt{50} = \sqrt{25 \times 2} = \sqrt{25} \cdot \sqrt{2} = 5\sqrt{2} \] Now, substituting these back into the denominator: \[ 5\sqrt{3} - 4\sqrt{3} - 4\sqrt{2} + 5\sqrt{2} \] Combine like terms: \[ (5\sqrt{3} - 4\sqrt{3}) + (-4\sqrt{2} + 5\sqrt{2}) = \sqrt{3} + \sqrt{2} \] ### Step 2: Rewrite the Expression Now, we can rewrite the expression: \[ \frac{3+\sqrt{6}}{\sqrt{3}+\sqrt{2}} \] ### Step 3: Rationalize the Denominator To rationalize the denominator, we multiply the numerator and denominator by the conjugate of the denominator, which is \(\sqrt{3}-\sqrt{2}\): \[ \frac{(3+\sqrt{6})(\sqrt{3}-\sqrt{2})}{(\sqrt{3}+\sqrt{2})(\sqrt{3}-\sqrt{2})} \] ### Step 4: Simplify the Denominator Using the difference of squares: \[ (\sqrt{3})^2 - (\sqrt{2})^2 = 3 - 2 = 1 \] ### Step 5: Expand the Numerator Now, we expand the numerator: \[ (3+\sqrt{6})(\sqrt{3}-\sqrt{2}) = 3\sqrt{3} - 3\sqrt{2} + \sqrt{6}\sqrt{3} - \sqrt{6}\sqrt{2} \] This simplifies to: \[ 3\sqrt{3} - 3\sqrt{2} + \sqrt{18} - \sqrt{12} \] Now, simplify \(\sqrt{18}\) and \(\sqrt{12}\): \[ \sqrt{18} = 3\sqrt{2}, \quad \sqrt{12} = 2\sqrt{3} \] Substituting these values back: \[ 3\sqrt{3} - 3\sqrt{2} + 3\sqrt{2} - 2\sqrt{3} \] Combine like terms: \[ (3\sqrt{3} - 2\sqrt{3}) + (-3\sqrt{2} + 3\sqrt{2}) = \sqrt{3} + 0 = \sqrt{3} \] ### Final Answer Thus, the value of the expression is: \[ \sqrt{3} \]
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