The angle of elevation of a cloud from a point h meter above the surface of the lake is `alpha`, the angle of depression of its reflection in the lake is `beta`. Prove that height of the cloud from observation points is `(2hsecalpha)/(tanbeta-tanalpha)`.

If the angle of elevation of a cloud from a point h metres above lake is alpha and the angle of depression of its reflection in the lake be beta , prove that the distance of the cloud from the point of observation is (2 h sec alpha)/(tan beta - tan alpha)

The angle of elevation of a cloud from a point h metre above a lake is theta The angle depression of its reflection in the lake is 45^(@) The height of the cloud is

If the angle of elevation of a cloud from a foot 4 meters above a lake is beta and the angle of depression of its reflection in the lake is alpha then the height is

The angle of elevation of a cloud from a point h mt. above is theta^@ and the angle of depression of its reflection in the lake is phi . Then, the height is

The angle of elevation of a stationary cloud from a point h meter above a lake is 15^(@) and angle of depression of its reflection in the lake is beta . Prove that height of the cloud above the lake is (h(tanbeta+tanalpha))/(tanbeta-tanalpha) .

If the angle of elevation of a cloud from a point 10 metres above a lake is 30^(@) and the angle of depression of its reflection in the lake is 60^(@) . Find the height of the cloud from the surface of lake.