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Let U= {1, 2, 3, 4, 5, 6, 7, 8,9}, A={1,...

Let U= {1, 2, 3, 4, 5, 6, 7, 8,9}, A={1, 2, 3, 4}, B = {2, 4, 6, 8) and C={3, 4, 5, 6}. Find
`(A')'`

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To solve the problem of finding \( (A')' \), where \( A' \) is the complement of set \( A \) and \( (A')' \) is the complement of the complement of \( A \), we can follow these steps: ### Step 1: Identify the Universal Set and Set A The universal set \( U \) is given as: \[ U = \{1, 2, 3, 4, 5, 6, 7, 8, 9\} \] Set \( A \) is given as: \[ A = \{1, 2, 3, 4\} \] ### Step 2: Find the Complement of Set A The complement of set \( A \), denoted as \( A' \), consists of all the elements in the universal set \( U \) that are not in \( A \). To find \( A' \): \[ A' = U - A \] \[ A' = \{1, 2, 3, 4, 5, 6, 7, 8, 9\} - \{1, 2, 3, 4\} \] \[ A' = \{5, 6, 7, 8, 9\} \] ### Step 3: Find the Complement of the Complement of Set A Now we need to find \( (A')' \), which is the complement of \( A' \). To find \( (A')' \): \[ (A')' = U - A' \] \[ (A')' = \{1, 2, 3, 4, 5, 6, 7, 8, 9\} - \{5, 6, 7, 8, 9\} \] \[ (A')' = \{1, 2, 3, 4\} \] ### Conclusion Thus, the result of \( (A')' \) is: \[ (A')' = \{1, 2, 3, 4\} \]
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