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If X and Y are two sets such that n(X)=1...

If X and Y are two sets such that n(X)=17,n(Y)=23 and `n(X uu Y)`=38, then `n( X nn Y)`

A

2

B

1

C

3

D

4

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will use the formula that relates the number of elements in the union and intersection of two sets. The formula is: \[ n(X \cup Y) = n(X) + n(Y) - n(X \cap Y) \] Where: - \( n(X \cup Y) \) is the number of elements in the union of sets X and Y. - \( n(X) \) is the number of elements in set X. - \( n(Y) \) is the number of elements in set Y. - \( n(X \cap Y) \) is the number of elements in the intersection of sets X and Y. ### Step-by-Step Solution: 1. **Identify the given values:** - \( n(X) = 17 \) - \( n(Y) = 23 \) - \( n(X \cup Y) = 38 \) 2. **Substitute the values into the formula:** \[ n(X \cup Y) = n(X) + n(Y) - n(X \cap Y) \] Substituting the known values: \[ 38 = 17 + 23 - n(X \cap Y) \] 3. **Simplify the equation:** - First, calculate \( 17 + 23 \): \[ 17 + 23 = 40 \] - Now substitute back into the equation: \[ 38 = 40 - n(X \cap Y) \] 4. **Rearrange to find \( n(X \cap Y) \):** \[ n(X \cap Y) = 40 - 38 \] \[ n(X \cap Y) = 2 \] 5. **Conclusion:** The number of elements in the intersection of sets X and Y is \( n(X \cap Y) = 2 \). ### Final Answer: \( n(X \cap Y) = 2 \)
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