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There are two concentric circular tracks...

There are two concentric circular tracks of radii 100 m and 102 m, respectively. A runs on the inner track and goes once round on the inner track in 1 min 30 sec, while B runs on the outer track in 1 min 32 sec. Who runs faster?

A

Both A and B are equal

B

A

C

B

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To determine who runs faster between A and B on their respective circular tracks, we will follow these steps: ### Step 1: Calculate the Circumference of Each Track The formula for the circumference \( C \) of a circle is given by: \[ C = 2 \pi r \] where \( r \) is the radius of the circle. **For A (Inner Track):** - Radius \( r_A = 100 \) m \[ C_A = 2 \pi (100) = 200\pi \approx 628 \text{ m} \] **For B (Outer Track):** - Radius \( r_B = 102 \) m \[ C_B = 2 \pi (102) = 204\pi \approx 640.8 \text{ m} \] ### Step 2: Convert Time Taken into Seconds - A takes 1 minute 30 seconds to complete one round: \[ \text{Time}_A = 1 \times 60 + 30 = 90 \text{ seconds} \] - B takes 1 minute 32 seconds to complete one round: \[ \text{Time}_B = 1 \times 60 + 32 = 92 \text{ seconds} \] ### Step 3: Calculate the Speed of Each Runner Speed is calculated using the formula: \[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} \] **For A:** \[ \text{Speed}_A = \frac{C_A}{\text{Time}_A} = \frac{628}{90} \approx 6.98 \text{ m/s} \] **For B:** \[ \text{Speed}_B = \frac{C_B}{\text{Time}_B} = \frac{640.8}{92} \approx 6.96 \text{ m/s} \] ### Step 4: Compare the Speeds Now we compare the speeds calculated: - Speed of A: \( 6.98 \text{ m/s} \) - Speed of B: \( 6.96 \text{ m/s} \) Since \( 6.98 \text{ m/s} > 6.96 \text{ m/s} \), A runs faster than B. ### Conclusion A runs faster than B. ---
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