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What is the area of a regular hexagon in...

What is the area of a regular hexagon inscribed in a circle of radius r ?

A

`2sqrt(3) r^(2)` sq. units

B

`(3sqrt(3))/(2) r^(2)` sq. units

C

`(2)/(3) r^(2)` sq. units

D

`(sqrt(3))/(2) r^(2)` sq. units

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The correct Answer is:
To find the area of a regular hexagon inscribed in a circle of radius \( r \), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Hexagon**: A regular hexagon can be divided into 6 equilateral triangles. Each triangle has its vertices at the center of the circle and two adjacent vertices of the hexagon. 2. **Finding the Side Length**: The radius of the circle is equal to the length of each side of the equilateral triangles. Therefore, if the radius of the circle is \( r \), then the side length \( s \) of the hexagon is also \( r \). 3. **Area of One Equilateral Triangle**: The area \( A \) of an equilateral triangle with side length \( s \) is given by the formula: \[ A = \frac{\sqrt{3}}{4} s^2 \] Substituting \( s = r \) into the formula, we get: \[ A = \frac{\sqrt{3}}{4} r^2 \] 4. **Total Area of the Hexagon**: Since the hexagon consists of 6 such triangles, the total area \( A_{hex} \) of the hexagon is: \[ A_{hex} = 6 \times A = 6 \times \frac{\sqrt{3}}{4} r^2 \] Simplifying this gives: \[ A_{hex} = \frac{6\sqrt{3}}{4} r^2 = \frac{3\sqrt{3}}{2} r^2 \] 5. **Final Result**: Therefore, the area of the regular hexagon inscribed in a circle of radius \( r \) is: \[ A_{hex} = \frac{3\sqrt{3}}{2} r^2 \]
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