Home
Class 14
MATHS
A conical tent of given capacity has to ...

A conical tent of given capacity has to be constructed. The ratio of the height to the radius of the base for the minimum area of canvas required for the tent is

A

`1 : 2`

B

`2 : 1`

C

`1 : sqrt(2)`

D

`sqrt(2) : 1`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the ratio of the height to the radius of the base of a conical tent for the minimum area of canvas required, we can follow these steps: ### Step 1: Understand the Geometry of the Cone A conical tent can be described by its radius \( r \) (of the base) and its height \( h \). The volume \( V \) of the cone is given by the formula: \[ V = \frac{1}{3} \pi r^2 h \] ### Step 2: Express Height in Terms of Radius and Volume From the volume formula, we can express the height \( h \) in terms of the radius \( r \) and the volume \( V \): \[ h = \frac{3V}{\pi r^2} \] ### Step 3: Calculate the Surface Area of the Cone The surface area \( A \) of the cone (which is the area of the canvas required) is given by: \[ A = \pi r^2 + \pi r l \] where \( l \) is the slant height of the cone. The slant height can be expressed using the Pythagorean theorem: \[ l = \sqrt{h^2 + r^2} \] Substituting \( h \) from Step 2: \[ l = \sqrt{\left(\frac{3V}{\pi r^2}\right)^2 + r^2} \] ### Step 4: Substitute \( l \) into the Surface Area Formula Now, substituting \( l \) into the surface area formula: \[ A = \pi r^2 + \pi r \sqrt{\left(\frac{3V}{\pi r^2}\right)^2 + r^2} \] ### Step 5: Differentiate the Surface Area with Respect to Radius To find the minimum surface area, we need to take the derivative of \( A \) with respect to \( r \) and set it to zero. This will give us: \[ \frac{dA}{dr} = 0 \] ### Step 6: Solve the Derivative Equation After differentiating and simplifying the equation, we will find a relationship between \( h \) and \( r \). This will involve some algebraic manipulation. ### Step 7: Find the Ratio \( \frac{h}{r} \) From the derived relationship, we will find the ratio of height to radius \( \frac{h}{r} \). After simplification, we will arrive at: \[ \frac{h}{r} = \sqrt{2} \] ### Conclusion Thus, the ratio of the height to the radius of the base for the minimum area of canvas required for the tent is: \[ \frac{h}{r} = \sqrt{2} \]
Promotional Banner

Topper's Solved these Questions

  • MENSURATION

    DISHA PUBLICATION|Exercise TEST YOURSELF|15 Videos
  • MENSURATION

    DISHA PUBLICATION|Exercise Practice Exercises (STANDARD LEVEL)|63 Videos
  • LOGARITHMS

    DISHA PUBLICATION|Exercise Test Yourself |15 Videos
  • MOCK TEST - 3

    DISHA PUBLICATION|Exercise Multiple Choice Questions|20 Videos

Similar Questions

Explore conceptually related problems

The area of canvas to be used in making the tent, is:

Prove that a conical tent of given capacity will require the least amount of canvas when the height is sqrt(2) xx the radius of the base.

A conical circus tent is to be made of canvas. The height of the tent is 35 m and the radius of the base is 84 m. If pi =(22)/7 , then the canvas required is :

Prove that a conical tent of given capacity will require the minimum when the ratio between the height of the cone and radius of its base is sqrt(2):1

A circus tent is cylindrical up to a height of 3m and conical above it. If its diameter is 105m and the slant height of the conical part is 63 m, then the total area of the canvas required to make the tent is (take pi = (22)/(7) )

A circus tent is cylindrical to a height of 3 meters and conical above it. If the radius of the base is 52.5 m and the slant height of the cone is 52 m,then the total area of the canvas required to make it is:

A tent is made in the form of a frustum of a cone surmounted by anoter cone. The diametere of the base top of the frustum are 20m and 6m respectvely, and the height is 24m. If the height of the tent is 28 m and the radius of the conical part is equal to the radius of the top of the frustum, fidn the quantity of can vas required. [ Take pi = 22/7 ]

DISHA PUBLICATION-MENSURATION-Practice Exercises (EXPERT LEVEL)
  1. Find the area of the shaded region if 'ABC is an equilateral triangle...

    Text Solution

    |

  2. A city has a park shaped as a right angled triangle. The length of the...

    Text Solution

    |

  3. A conical tent of given capacity has to be constructed. The ratio of t...

    Text Solution

    |

  4. A circus tent is cylindrical to a height of 3 metres and conical above...

    Text Solution

    |

  5. All five faces of a regular pyramid with a square base are found to be...

    Text Solution

    |

  6. There are 300 coins, each coin having radius 2 cm and height 1 cm. The...

    Text Solution

    |

  7. Find the ratio of the areas of an equilateral triangle ABC and square ...

    Text Solution

    |

  8. In a triangle ABC, the lengths of the sides AB and AC equal to 17.5 cm...

    Text Solution

    |

  9. In rectangle ABCD, E, F and G, H are points of trisection of AB and AD...

    Text Solution

    |

  10. In the given figure below, the boundary of the shaded re- gion compris...

    Text Solution

    |

  11. Find the area of the shaded region in the diagram below where the give...

    Text Solution

    |

  12. Find the area of the shaded region. [All the circles shown in the figu...

    Text Solution

    |

  13. A right circular cone is divided into 3 portions A<ltB and C by planes...

    Text Solution

    |

  14. Answer the questions on the basis of the information given Consider a ...

    Text Solution

    |

  15. Answer the questions on the basis of the information given Consider a ...

    Text Solution

    |

  16. Answer the questions on the basis of the information given Consider a ...

    Text Solution

    |

  17. What is the area of the shaded region show, if the radius of each circ...

    Text Solution

    |

  18. If AB = 10 cm, what is the area of the shaded portion ? it is given th...

    Text Solution

    |

  19. In the diagram AD = DB and AH = HD Find the ratio of the area of the s...

    Text Solution

    |

  20. Carpenter Rajesh has a circular piece of plywood of diameter 30 feet. ...

    Text Solution

    |