If veca = 2hati - 3 hatj, vecb = - hati+...

If `veca = 2hati - 3 hatj, vecb = - hati+ hatk , vecc = 2hatj- hatk` find the area of the parallelogram having diagonals `veca + vecb ` and `vecb + vecc ` .

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The correct Answer is:

`(sqrt(21))/(2)`

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