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A metal rod of length 1.5 m rotates abou...

A metal rod of length 1.5 m rotates about one end in a vertical plane at right angles to the magnetic meridian. If the frequency of revolution is 1200 rpm, find the induced emf between the ends of the rod. (Horizontal intensity of the earth's field = `3.2xx10^(-5)T` )

Text Solution

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Here, length of rod, R = 1.5m
Frequency of revolution, v = 1200 rpm
= `(1200)/60 = 20` m/s
Magnetic field, `B = 3.2 xx10^(-5) T`
Induced emf, `e = 1/2 BR^(2) omega`
`=1/2BR^(2) (2piv)`
`=1/2 (3.2 xx10^(-5))xx(1.5)^2 xx 2 xx pi xx 20`
`= 4.52 xx10^(-3) V`
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