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Electric current is changing through the...

Electric current is changing through the coil of self-inductance 5 mH as `i =(3l^(2)+ + 4t)` A, where, t is time in seconds. Find the induced emf generated in the coil at t = 2 s.

Text Solution

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As we know, induced emf is given by
`epsilon=L |(di)/(dt)|=5 xx10^(-3)xxd/(dt) (3t^2 +4t)`
`= 5 xx10^(-3)xx(6t +4)`
At time t = 2 s, we get
Induced emf, `epsilon= 5xx10^(-3) xx (6 xx2 +4)`
`= 5 xx10^(-3) xx(16) = 80 xx10^(-3)`
`= 8 xx10^(-2) =0.08 V`
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